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Control Systems Engineering•Unit 2• EEE2005

Time Response Analysis & Transient Specifications

Standard test signals, first-order step and impulse responses, prototype second-order system dynamics across undamped, underdamped, critically damped, and overdamped regimes, transient response specifications (delay, rise, peak time, %Mp, and settling time), steady-state error analysis, static error constants (Kp, Kv, Ka), and system types.

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Skills Built:Canonical Second-Order System Parameterization (ωn, ζ, σ, ωd)Transient Specifications Derivation (td, tr, tp, %Mp, ts)Damping Regime Identification & Real vs Complex Root DynamicsStatic Error Constants (Kp, Kv, Ka) & Tracking Error FormulationSystem Type 0, 1, 2 Steady-State Error MatrixComplex s-Plane Constant-ζ Rays & Constant-ωn CirclesHigher-Order Dominant Pole Approximation (|p3| ≥ 5ζωn)

1. 5 Key Ideas: Time-Domain Dynamics & Performance Metrics

Idea 1: Standard Test Signals & Dynamic Characterization

In physical engineering systems, future operational command signals cannot be known a priori. Control systems are therefore benchmarked against four standardized canonical test signals:

  1. Unit Impulse δ(t)\delta(t): Models sudden shock or impact loads (e.g., lightning strikes, gust disturbances, hammer impact). Laplace transform: R(s)=1R(s) = 1. The impulse response g(t)=L−1[G(s)]g(t) = \mathcal{L}^{-1}[G(s)] represents the natural unforced dynamic weighting function of the system.
  2. Unit Step u(t)u(t): Models an instantaneous command change or setpoint jump (e.g., flipping a cruise control switch, changing an oven thermostat). Laplace transform: R(s)=1sR(s) = \frac{1}{s}. Used to evaluate transient overshoot, rise time, and positional accuracy.
  3. Unit Ramp r(t)=t⋅u(t)r(t) = t \cdot u(t): Models a constant-velocity tracking command (e.g., radar tracking an aircraft moving at constant speed). Laplace transform: R(s)=1s2R(s) = \frac{1}{s^2}. Used to evaluate velocity tracking lag (KvK_v).
  4. Unit Parabolic p(t)=12t2⋅u(t)p(t) = \frac{1}{2} t^2 \cdot u(t): Models constant acceleration tracking (e.g., tracking a missile accelerating off a launch pad). Laplace transform: R(s)=1s3R(s) = \frac{1}{s^3}. Used to evaluate acceleration error (KaK_a).

Idea 2: First-Order Systems & The Universal Time Constant

The canonical first-order closed-loop transfer function with DC gain KK and time constant τ\tau is: T(s)=C(s)R(s)=K1+sτ=K/τs+1/τT(s) = \frac{C(s)}{R(s)} = \frac{K}{1 + s\tau} = \frac{K/\tau}{s + 1/\tau}

Under a unit step input R(s)=1/sR(s) = 1/s, partial fraction expansion yields the classic exponential charging response: c(t)=K(1−e−t/τ)c(t) = K \left(1 - e^{-t/\tau}\right)

Key milestones define the first-order response:

  • At t=τt = \tau: c(τ)=K(1−e−1)≈0.632Kc(\tau) = K(1 - e^{-1}) \approx 0.632 K (63.2%63.2\% of final value).
  • At t=2τt = 2\tau: c(2τ)=K(1−e−2)≈0.865Kc(2\tau) = K(1 - e^{-2}) \approx 0.865 K (86.5%86.5\%).
  • At t=3τt = 3\tau: c(3τ)≈0.950Kc(3\tau) \approx 0.950 K (enters the 5%5\% settling band; ts=3τt_s = 3\tau).
  • At t=4τt = 4\tau: c(4τ)≈0.982Kc(4\tau) \approx 0.982 K (enters the 2%2\% settling band; ts=4τt_s = 4\tau).
  • Initial slope at t=0t=0: dcdt∣t=0=Kτ\left.\frac{dc}{dt}\right|_{t=0} = \frac{K}{\tau}. If the initial rate of rise were maintained, the response would reach KK in exactly one time constant τ\tau.

Idea 3: The Second-Order Prototype & 4 Canonical Damping Regimes

Feedback control systems are predominantly analyzed using the canonical second-order prototype transfer function: T(s)=C(s)R(s)=ωn2s2+2ζωns+ωn2T(s) = \frac{C(s)}{R(s)} = \frac{\omega_n^2}{s^2 + 2\zeta\omega_n s + \omega_n^2}

The characteristic equation s2+2ζωns+ωn2=0s^2 + 2\zeta\omega_n s + \omega_n^2 = 0 yields two roots (poles): s1,2=−ζωn±ωnζ2−1=−σ±jωds_{1,2} = -\zeta\omega_n \pm \omega_n \sqrt{\zeta^2 - 1} = -\sigma \pm j\omega_d

Where:

  • ωn\omega_n: Undamped Natural Frequency (rad/s) — the frequency at which the system would oscillate if all damping were removed.
  • ζ\zeta: Damping Ratio (dimensionless) — ratio of actual damping to critical damping (ζ=B/Bc\zeta = B / B_c).
  • σ=ζωn\sigma = \zeta\omega_n: Attenuation / Damping Factor (rad/s) — governs the exponential decay rate (e−σte^{-\sigma t}).
  • ωd=ωn1−ζ2\omega_d = \omega_n \sqrt{1 - \zeta^2}: Damped Natural Frequency (rad/s) — the actual frequency of transient oscillation.

The value of ζ\zeta partitions the system into four fundamentally distinct dynamic regimes:

  1. Undamped (ζ=0\zeta = 0): Pure imaginary roots s1,2=±jωns_{1,2} = \pm j\omega_n. Continuous undamped sinusoidal oscillation: c(t)=1−cos⁡(ωnt)c(t) = 1 - \cos(\omega_n t). No energy dissipation.
  2. Underdamped (0<ζ<10 < \zeta < 1): Complex conjugate roots in the left-half s-plane (s1,2=−σ±jωds_{1,2} = -\sigma \pm j\omega_d). Oscillatory transient with exponentially decaying envelope: c(t)=1−e−ζωnt1−ζ2sin⁡(ωdt+θ),θ=cos⁡−1(ζ)c(t) = 1 - \frac{e^{-\zeta\omega_n t}}{\sqrt{1-\zeta^2}} \sin(\omega_d t + \theta), \quad \theta = \cos^{-1}(\zeta)
  3. Critically Damped (ζ=1\zeta = 1): Two identical negative real roots s1,2=−ωns_{1,2} = -\omega_n. Fastest possible non-oscillatory return to steady state: c(t)=1−e−ωnt(1+ωnt)c(t) = 1 - e^{-\omega_n t}(1 + \omega_n t)
  4. Overdamped (ζ>1\zeta > 1): Two distinct negative real roots s1,2=−ζωn±ωnζ2−1s_{1,2} = -\zeta\omega_n \pm \omega_n\sqrt{\zeta^2-1}. Sluggish exponential response dominated by the slower pole: c(t)=1+s2es1t−s1es2ts1−s2c(t) = 1 + \frac{s_2 e^{s_1 t} - s_1 e^{s_2 t}}{s_1 - s_2}

Idea 4: Time-Domain Transient Specifications & The Optimal ζ≈0.707\zeta \approx 0.707

To quantify the performance of underdamped systems, five standardized time-domain specifications are defined for a unit step input:

  1. Delay Time (tdt_d): Time required for the response to reach 50%50\% of its final steady-state value: td≈1+0.7ζωnt_d \approx \frac{1 + 0.7\zeta}{\omega_n}
  2. Rise Time (trt_r): Time required for the response to rise from 10%10\% to 90%90\% (overdamped) or 0%0\% to 100%100\% (underdamped) of its final value: tr=π−θωd,where θ=tan⁡−1(1−ζ2ζ) [in radians]t_r = \frac{\pi - \theta}{\omega_d}, \quad \text{where } \theta = \tan^{-1}\left(\frac{\sqrt{1-\zeta^2}}{\zeta}\right) \text{ [in radians]}
  3. Peak Time (tpt_p): Time required for the response to reach the first peak of the overshoot: tp=πωd=πωn1−ζ2t_p = \frac{\pi}{\omega_d} = \frac{\pi}{\omega_n \sqrt{1-\zeta^2}}
  4. Maximum Percentage Overshoot (%Mp\%M_p): Normalized magnitude of the first peak above unity: %Mp=c(tp)−c(∞)c(∞)×100%=e−πζ1−ζ2×100%\%M_p = \frac{c(t_p) - c(\infty)}{c(\infty)} \times 100\% = e^{-\frac{\pi\zeta}{\sqrt{1-\zeta^2}}} \times 100\% Critical Insight: %Mp\%M_p depends strictly and solely on the damping ratio ζ\zeta, completely independent of the natural frequency ωn\omega_n!
  5. Settling Time (tst_s): Time required for the response curve to enter and permanently remain within a specified tolerance band around the steady-state value:
    • For 2%2\% tolerance band (±0.02\pm 0.02): ts=4ζωn=4τt_s = \frac{4}{\zeta\omega_n} = 4\tau
    • For 5%5\% tolerance band (±0.05\pm 0.05): ts=3ζωn=3τt_s = \frac{3}{\zeta\omega_n} = 3\tau

The Optimal ζ=0.707\zeta = 0.707 Compromise: Control engineers rarely design for ζ=1\zeta = 1 because the response is too sluggish, nor for ζ<0.4\zeta < 0.4 because overshoot exceeds 25%25\%. Choosing ζ=1/2≈0.707\zeta = 1/\sqrt{2} \approx 0.707 provides a rapid rise time with an exceptionally modest peak overshoot of only %Mp≈4.3%\%M_p \approx 4.3\%.

Idea 5: Steady-State Error (esse_{ss}), Final Value Theorem & System Types

Steady-state error (esse_{ss}) measures the tracking accuracy of a control system after all transient oscillations have decayed to zero (t→∞t \to \infty). For a unity feedback control system with open-loop transfer function G(s)G(s), the error signal is E(s)=R(s)1+G(s)E(s) = \frac{R(s)}{1 + G(s)}. Applying the Laplace Final Value Theorem: ess=lim⁡t→∞e(t)=lim⁡s→0sE(s)=lim⁡s→0sR(s)1+G(s)e_{ss} = \lim_{t\to\infty} e(t) = \lim_{s\to 0} s E(s) = \lim_{s\to 0} \frac{s R(s)}{1 + G(s)}

The general open-loop transfer function is expressed in terms of its pole at the origin (integrators): G(s)=K(1+sTa)(1+sTb)…sN(1+sT1)(1+sT2)…G(s) = \frac{K (1 + s T_a)(1 + s T_b)\dots}{s^N (1 + s T_1)(1 + s T_2)\dots} Where NN is the System Type Number (number of pure integrators at s=0s=0).

The tracking ability is governed by three Static Error Constants:

  • Positional Error Constant (KpK_p): Kp=lim⁡s→0G(s)  ⟹  ess(step)=11+KpK_p = \lim_{s\to 0} G(s) \implies e_{ss}(\text{step}) = \frac{1}{1 + K_p}
  • Velocity Error Constant (KvK_v): Kv=lim⁡s→0sG(s)  ⟹  ess(ramp)=1KvK_v = \lim_{s\to 0} s G(s) \implies e_{ss}(\text{ramp}) = \frac{1}{K_v}
  • Acceleration Error Constant (KaK_a): Ka=lim⁡s→0s2G(s)  ⟹  ess(parabolic)=1KaK_a = \lim_{s\to 0} s^2 G(s) \implies e_{ss}(\text{parabolic}) = \frac{1}{K_a}

| System Type | Step Input r(t)=1r(t) = 1 | Ramp Input r(t)=tr(t) = t | Parabolic Input r(t)=12t2r(t) = \frac{1}{2}t^2 | | :--- | :--- | :--- | :--- | | Type 0 (N=0N=0) | ess=11+Kpe_{ss} = \frac{1}{1 + K_p} (Finite) | ess=∞e_{ss} = \infty (Unbounded) | ess=∞e_{ss} = \infty (Unbounded) | | Type 1 (N=1N=1) | ess=0e_{ss} = 0 (Zero error) | ess=1Kve_{ss} = \frac{1}{K_v} (Finite lag) | ess=∞e_{ss} = \infty (Unbounded) | | Type 2 (N=2N=2) | ess=0e_{ss} = 0 (Zero error) | ess=0e_{ss} = 0 (Zero error) | ess=1Kae_{ss} = \frac{1}{K_a} (Finite lag) |


2. Formula & Unit Quick-Reference Strip

Formula & Unit Quick-Reference Strip
Second-Order Closed Loop TFDimensionless Transfer Ratio
T(s) = omega_n^2 / (s^2 + 2*zeta*omega_n*s + omega_n^2)

Canonical standard prototype governing second-order closed-loop feedback systems.

Damped Natural Frequencyrad/s
omega_d = omega_n * sqrt(1 - zeta^2)

Actual angular frequency of transient sinusoidal oscillation under damping ratio zeta < 1.

Rise Time (tr)Seconds (s)
t_r = (pi - theta) / omega_d, theta = acos(zeta)

Time required for underdamped step response to rise from 0% to 100% of final value.

Peak Time (tp)Seconds (s)
t_p = pi / omega_d = pi / (omega_n * sqrt(1 - zeta^2))

Time required to reach the very first peak of transient overshoot.

Maximum Peak Overshoot (%Mp)Percentage (%)
%M_p = exp(-pi*zeta / sqrt(1 - zeta^2)) * 100%

Peak transient overshoot magnitude above final value, dependent strictly on damping ratio zeta.

Settling Time (2% and 5%)Seconds (s)
t_s(2%) = 4 / (zeta*omega_n), t_s(5%) = 3 / (zeta*omega_n)

Time for transient envelope to decay and remain permanently within specified tolerance bands.

Static Positional Constant (Kp)Static Loop Gain Constant
K_p = lim(s->0) G(s)H(s) => e_ss = 1 / (1 + K_p)

Figure of merit for step input tracking; Type 0 has finite error, Type 1+ has zero error.

Static Velocity Constant (Kv)sec^-1
K_v = lim(s->0) s*G(s)H(s) => e_ss = 1 / K_v

Figure of merit for ramp tracking; Type 1 has finite velocity lag, Type 2 has zero error.

Static Acceleration Constant (Ka)sec^-2
K_a = lim(s->0) s^2*G(s)H(s) => e_ss = 1 / K_a

Figure of merit for parabolic acceleration tracking; Type 2 has finite lag.


3. Mathematical Derivations: Transient Specifications & Error Constants


4. Typical Laboratory Hardware Values & Engineering Benchmarks

Typical Laboratory Hardware Ranges
Parameter / PartTypical ValueLab RangePractical Notes
Precision Servomotor Drive (Robotics)ζ = 0.65 - 0.720.50 - 0.85Optimal balance: Mp < 5%, fast rise time tr < 80ms, robust phase margin.
Hard Disk Drive Head ActuatorSeek time < 4 ms2 - 8 msCritically damped approximation (ζ ≈ 0.8) to prevent track overshoot and head crashes.
Utility Power Grid Frequency Loopts < 4.0 s (2% band)2.0 - 6.0 sGovernor droop control tuned for overdamped / heavily damped regime (ζ ≈ 0.85 - 1.1).
Satellite Attitude Reaction Wheelζ ≈ 0.500.40 - 0.60Fuel-constrained reaction thrusters allow modest overshoot (Mp ≈ 16%) to conserve fuel mass.
Dominant Pole Ratio (|p3| / ζωn)≥ 5.0×3.0× - 10.0×If real pole is 5× farther to the left than complex pair, its transient decays in 1/5th the time.

5. Worked Examples: Step-by-Step Analytical Solutions

Step-by-Step Worked Problem

[Presidency University Exam Problem] A unity feedback control system has open-loop transfer function G(s) = 25 / [s(s + 6)]. Determine: (1) The undamped natural frequency ωn and damping ratio ζ, (2) The damped natural frequency ωd, (3) The delay time td, (4) The rise time tr, (5) The peak time tp, (6) The percentage maximum overshoot %Mp, and (7) The settling time ts for both 2% and 5% tolerance criteria.

Step 1: Obtain the closed-loop transfer function T(s)
T(s) = G(s) / [1 + G(s)] = 25 / [s(s + 6) + 25] = 25 / (s^2 + 6s + 25). Comparing with standard form: s^2 + 2*zeta*omega_n*s + omega_n^2 = 0: omega_n^2 = 25 => omega_n = 5 rad/s. 2*zeta*omega_n = 6 => 2*zeta*(5) = 6 => zeta = 6 / 10 = 0.6 (Underdamped).
Step 2: Calculate damped natural frequency ωd and angle θ
omega_d = omega_n * sqrt(1 - zeta^2) = 5 * sqrt(1 - 0.36) = 5 * sqrt(0.64) = 5 * 0.8 = 4 rad/s. theta = acos(zeta) = acos(0.6) = 0.9273 radians (or 53.13°).
Step 3: Calculate Delay Time td and Rise Time tr
Delay time: t_d ≈ (1 + 0.7*zeta) / omega_n = (1 + 0.7*0.6) / 5 = (1 + 0.42) / 5 = 1.42 / 5 = 0.284 s. Rise time: t_r = (pi - theta) / omega_d = (3.1416 - 0.9273) / 4 = 2.2143 / 4 = 0.5536 s ≈ 0.554 s.
Step 4: Calculate Peak Time tp and Maximum Peak Overshoot %Mp
Peak time: t_p = pi / omega_d = 3.1416 / 4 = 0.7854 s ≈ 0.785 s. Percentage overshoot: %M_p = exp(-pi*zeta / sqrt(1 - zeta^2)) * 100% %M_p = exp(-pi*0.6 / 0.8) * 100% = exp(-2.3562) * 100% = 0.09478 * 100% = 9.48%.
Step 5: Calculate Settling Time ts (2% and 5% bands)
Damping factor sigma = zeta * omega_n = 0.6 * 5 = 3.0 rad/s. For 2% criterion: t_s = 4 / sigma = 4 / 3 = 1.333 s. For 5% criterion: t_s = 3 / sigma = 3 / 3 = 1.000 s.
Step-by-Step Worked Problem

[Control Loop Design Problem] A position servomechanism with plant G(s) = K / [s(s + a)] in unity negative feedback is required to satisfy two design specifications: (1) Maximum peak overshoot %Mp ≤ 16.3%, and (2) Peak time tp ≤ 1.0 second. Compute the required numerical values for system gain K and plant parameter a.

Step 1: Determine damping ratio ζ from the overshoot specification
%M_p = exp(-pi*zeta / sqrt(1 - zeta^2)) * 100% = 16.3% => 0.163. Taking natural logarithm on both sides: -pi*zeta / sqrt(1 - zeta^2) = ln(0.163) = -1.814 pi^2 * zeta^2 / (1 - zeta^2) = (-1.814)^2 = 3.291 9.8696 * zeta^2 = 3.291 - 3.291 * zeta^2 13.161 * zeta^2 = 3.291 => zeta^2 = 0.250 => zeta = 0.50.
Step 2: Determine natural frequency ωn from the peak time specification
t_p = pi / (omega_n * sqrt(1 - zeta^2)) = 1.0 s omega_n * sqrt(1 - (0.5)^2) = pi omega_n * sqrt(0.75) = 3.1416 => omega_n * 0.8660 = 3.1416 omega_n = 3.1416 / 0.8660 = 3.6276 rad/s.
Step 3: Relate design parameters to the closed-loop characteristic equation
Closed-loop transfer function: T(s) = K / (s^2 + as + K). Comparing with standard form s^2 + 2*zeta*omega_n*s + omega_n^2: omega_n^2 = K => K = (3.6276)^2 = 13.16 a = 2 * zeta * omega_n = 2 * (0.50) * 3.6276 = 3.628.
Step-by-Step Worked Problem

[Steady-State Error Analysis] A unity feedback system has open-loop transfer function G(s) = 20(s + 2) / [s(s + 1)(s + 4)]. (1) Identify the system type number, (2) Evaluate the static error constants Kp, Kv, Ka, and (3) Calculate the steady-state tracking error ess for three inputs: r1(t) = 5 u(t), r2(t) = 3t u(t), and r3(t) = 2t^2 u(t).

Step 1: Identify System Type Number
The open loop G(s) has a factor of s^1 in the denominator, meaning there is exactly one pole at the origin s = 0. Therefore, the system is a Type 1 system.
Step 2: Compute Static Positional Error Constant Kp
K_p = lim(s->0) G(s) = lim(s->0) [20(s + 2)] / [s(s + 1)(s + 4)] = [20(2)] / [0 * 1 * 4] = 40 / 0 = ∞. For step input r1(t) = 5 u(t) (magnitude A = 5): e_ss1 = A / (1 + K_p) = 5 / (1 + ∞) = 0.0 (Zero steady-state positional error).
Step 3: Compute Static Velocity Error Constant Kv
K_v = lim(s->0) s * G(s) = lim(s->0) [s * 20(s + 2)] / [s(s + 1)(s + 4)] = [20(2)] / [(1)(4)] = 40 / 4 = 10 sec^-1. For ramp input r2(t) = 3t u(t) (ramp slope A = 3): e_ss2 = A / K_v = 3 / 10 = 0.300 units of lag.
Step 4: Compute Static Acceleration Error Constant Ka
K_a = lim(s->0) s^2 * G(s) = lim(s->0) [s^2 * 20(s + 2)] / [s(s + 1)(s + 4)] = 0 * [40 / 4] = 0. For parabolic input r3(t) = 2t^2 u(t) (expressed as (1/2)*A_acc*t^2 => A_acc = 4): e_ss3 = A_acc / K_a = 4 / 0 = ∞ (Error grows without bound over time).

6. Common Exam Traps & Where Marks Are Lost

Common Exam Traps & Where Marks Are Lost

Avoid these classic calculation errors frequently spotted on semester examination answer scripts:

  • Ramp Error Input Coefficient Confusion: When evaluating steady-state error for a ramp input r(t) = 5t, the error is e_ss = 5 / Kv. However, for a parabolic input r(t) = 3t^2, remember that the standard Laplace transform is L[t^2] = 2! / s^3 = 2 / s^3. The standard polynomial form is r(t) = 0.5 * A * t^2. If r(t) = 3t^2, then 0.5 * A = 3 => A = 6! Writing e_ss = 3 / Ka instead of 6 / Ka is a frequent source of lost marks.
  • Overshoot Equation Inversion: When given %Mp = 10% and solving for ζ, students frequently miscalculate ln(0.10) or forget the negative sign in -ln(0.10) / sqrt(pi^2 + ln^2(0.10)). Remember: as %Mp approaches 0%, ζ approaches 1.0; as %Mp approaches 100%, ζ approaches 0.0.
  • Rise Time Definition Ambiguity: In underdamped systems, rise time tr is universally defined from 0% to 100% of final value, governed by tr = (pi - theta) / omega_d. In overdamped systems (zeta > 1), the response never reaches 100% in finite time, so tr is defined as the 10% to 90% rise time (tr ≈ 2.2 / omega_n for critical damping). Never apply the (pi - theta)/omega_d formula to overdamped or critically damped systems!
  • Dominant Pole Ratio Threshold: When reducing a third-order system to a second-order prototype via dominant pole approximation, the third real pole p3 MUST be at least 5 times farther from the imaginary axis than the real part of the complex conjugate pair: |p3| ≥ 5 * (zeta * omega_n). If |p3| = 2 * (zeta * omega_n), the third pole will substantially suppress the peak overshoot and prolong rise time, invalidating standard second-order formulas.
  • Settling Time Criterion Mixup: Always check whether the problem specifies a 2% tolerance band or a 5% tolerance band. For 2%: ts = 4 / (zeta * omega_n). For 5%: ts = 3 / (zeta * omega_n). Confusing the factor of 4 with 3 loses full credit on final answers.

7. Interactive Circuit Verification & Laboratory Workbench

Experiment with second-order time response curves, transient specifications, steady-state tracking errors, and complex s-plane pole placement in the live engineering simulator below:

Interactive Engineering Simulator
control-time-response

Simulator will mount when scrolled into view (conserving CPU & memory)

Try Breaking It: Predict Before You Test

What happens to the peak overshoot %Mp and peak time tp if you double the natural frequency ωn while holding the damping ratio ζ constant?


8. Parametric Practice Problem

Parametrised Practice Problem

Thévenin Equivalent of a Loaded Voltage Divider

A 24 V DC voltage source powers a divider with R1 = 100 Ω and R2 = 40 Ω. Calculate the open-circuit Thévenin voltage V_th (in Volts) appearing across terminals of R2.

V
Progressive Hints:

9. Unit Mastery Quiz

5-Question Mastery Check

Unit Quiz: Time Response Analysis & Transient Specifications

Q1.A canonical second-order system has closed-loop transfer function T(s) = 100 / (s^2 + 10s + 100). What is its damping regime?

Q2.Which of the following transient specifications depends strictly and solely on the damping ratio ζ, independent of the natural frequency ωn?

Q3.A unity negative feedback system with Type 1 open-loop transfer function is excited by a unit ramp input r(t) = t. What is its steady-state error?

Q4.Under the 2% tolerance criterion, what is the settling time ts of a second-order system with damping factor σ = ζωn = 2.5 rad/s?

Q5.Why do control engineers frequently target a damping ratio of ζ ≈ 0.707 in servomechanism design?

Q6.According to the Dominant Pole Rule of Thumb, when can a higher-order real pole at s = -p3 be neglected in transient analysis?

0 of 6 answered

10. References & Further Reading

  1. Ogata, Katsuhiko: Modern Control Engineering, 5th Edition, Prentice Hall (Chapters 5 & 6: Transient and Steady-State Response Analyses).
  2. Nise, Norman S.: Control Systems Engineering, 8th Edition, John Wiley & Sons (Chapter 4: Time Response).
  3. Dorf, Richard C., and Robert H. Bishop: Modern Control Systems, 13th Edition, Pearson.
  4. Presidency University Courseware: EEE2005 - Control Systems Engineering, Department of Electrical & Electronics Engineering, Bengaluru.